如题，请指教。

#include <iostream>
这是我找的答案，仅供参考


#include <limits>
#include <typeinfo>

template<typename T>
struct Type {
   static void print() {
      std::cout << typeid(T).name() << ": range is ("
                << std::numeric_limits<T>::min() << ", "
                << std::numeric_limits<T>::max() << ")\n";
   }
};

int main() {
   Type<char>::print();
   Type<short>::print();
   Type<int>::print();
   Type<long>::print();
   Type<float>::print();
   Type<double>::print();
   Type<long double>::print(); // Some compilers will not handle this one well
   Type<unsigned>::print();
   system("pause");
   return 0;
}



输出如下：
c: range is (

输出是：

c: range is (

输出如下：
关于c的那行有点问题，抱歉啊！

s: range is (-32768, 32767)
i: range is (-2147483648, 2147483647)
l: range is (-2147483648, 2147483647)
f: range is (1.17549e-038, 3.40282e+038)
d: range is (2.22507e-308, 1.79769e+308)
e: range is (0, 1.#INF)
j: range is (0, 4294967295)

#include <climit.h>

在Dev-C++上运行时会报错

就这个题而言，应该和sizeof没有关系吧！