题目还多个减号!

努力—前进—变老—退休—入土
2009-10-24 12:30
谢谢美女大侠的指点。。弄出来了。。
2009-10-24 12:43
2009-10-24 12:47
程序代码:#include <stdio.h>
long tigui(long jia,long cheng)
{
if(cheng%jia==0)
return jia;
else
tigui(cheng%jia,jia);
}
void yuefen(long *jia,long *cheng)
{
int i;
while(1)
{
i=tigui(*jia,*cheng);
if(i==1)break;
else
{
*jia/=i;
*cheng/=i;
}
}
}
int main(void)
{
int i,n,m=3,k=0;
unsigned long zi,mu;
do{
printf("n=");
scanf("%d",&n);
}while(n<1);
for(zi=1,mu=2,i=3;i<=n;i++)
{
k++;
if(k==m)
{
k=0,m++;
zi=zi*i-mu;
}
else
zi=mu+zi*i;
mu*=i;
yuefen(&zi,&mu);
}
printf("s=");
if(zi>mu)
{
printf("%ld+",zi/mu);
zi%=mu;
}
n==1?printf("1\n\n"):printf("%ld/%ld\n\n",zi,mu);
getch();
return 0;
}
2009-10-24 12:50
2009-10-24 12:51
程序代码:#include <stdio.h>
int main()
{
long i,m=1,n,x,y,z=1;
scanf("%d",&n);
for(i=1;i<=n;i++)
m=m*i;
z=m;
for(x=2;x<=n;x++)
if(x%2==0)
{
y=-x;
z=z+m/y;
}
else
{
z=z+m/x;
}
printf("%d/%d",z,m);
}
2009-10-24 13:10
2009-10-24 14:13
2009-10-24 14:18

2009-10-24 14:26

2009-10-24 16:21